Memo
로직 설명
•
반복되는 규칙에 맞는 리스트를 출력합니다.
Code
제출 날짜
@6/12/2021
import sys
R, C, N = map(int, sys.stdin.readline().split())
g_map = [sys.stdin.readline().strip() for i in range(R)]
second_map = [['O' for _ in range(C)] for _ in range(R)]
third_map = [['O' for _ in range(C)] for _ in range(R)]
dx = (0, 0, 1, -1)
dy = (1, -1, 0, 0)
for i in range(R):
for j in range(C):
if (g_map[i][j] == 'O'):
second_map[i][j] = '.'
for k in range(4):
ny = dy[k] + i
nx = dx[k] + j
if (ny < 0 or ny >= R or nx < 0 or nx >= C or second_map[ny][nx] == '.'):
continue
second_map[ny][nx] = '.'
for i in range(R):
for j in range(C):
if (second_map[i][j] == 'O'):
third_map[i][j] = '.'
for k in range(4):
ny = dy[k] + i
nx = dx[k] + j
if (ny < 0 or ny >= R or nx < 0 or nx >= C or third_map[ny][nx] == '.'):
continue
third_map[ny][nx] = '.'
def print_map(li):
for i in li:
for j in i:
print(j, end="")
print()
if (N == 1):
print_map(g_map)
exit(0)
if (not N % 2):
li = [['O' for _ in range(C)] for _ in range(R)]
for i in li:
for j in i:
print(j, end="")
print()
exit(0)
if (N % 4 == 1):
print_map(third_map)
elif (N % 4 == 3):
print_map(second_map)
Python
복사
